2c^2+4c-(23/2)

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Solution for 2c^2+4c-(23/2) equation: 


c in (-oo:+oo)

2*c^2+4*c-(23/2) = 0

2*c^2+4*c-23/2 = 0

2*c^2+4*c-23/2 = 0

DELTA = 4^2-(-23/2*2*4)

DELTA = 108

DELTA > 0

c = (108^(1/2)-4)/(2*2) or c = (-108^(1/2)-4)/(2*2)

c = (6*3^(1/2)-4)/4 or c = (-6*3^(1/2)-4)/4

c in { (-6*3^(1/2)-4)/4, (6*3^(1/2)-4)/4 }

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